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Can you mark me brainlest?
The answer to this question will depend on the function f itself. Basically you will find the height in meters above the ground of the bird when it jumped when the time t=0s. This is substsitute every t in the function for a value of zero and that way you will get the bird's height at the time it jumped. If you were given a graph for this function, you can find the y-intercept of the graph and that will be the answer as well. The question could be written like this:
A baby bird jumps from a tree branch and flutters to the ground. The function "
" models the bird's height (in meters) above the ground as a function of time (in seconds) after jumping. What is bird's height above the ground when it jumped.
Answer:
25m
Step-by-step explanation:
Once your function is given, you can substitute t=0 since 0s is the time measured at the moment the bird jumped. So our function will be:
So the height of the bird above the ground when it jumped is 25m in this particular function.
Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given
Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.
This gives:
Collect Like Terms
Solve for P
This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:
<em>Hence, the equilibrium quantity is 26.4</em>
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
$192
Step-by-step explanation:
2400/48=50
50x3.84=192
