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Advocard [28]
3 years ago
5

Find the midpoint of the line segment with the given endpoints(3, -5) and (7,9)

Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0

Answer:

Step-by-step explanation:

(x₁ , y₁) = (3 , -5)    & (x₂, y₂) = (7 , 9)

Midpoint = (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})

               =(\frac{3+7}{2} , \frac{-5+9}{2})\\\\=(\frac{10}{2} , \frac{4}{2})\\\\=(5 , 2)

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What is -(5x+6)-x=-6-6x
Veronika [31]

Answer: All real numbers are solutions.

Step-by-step explanation:

<u>Let's solve your equation step-by-step.</u>

−(5x+6)−x=−6−6x

<u>Step 1: Simplify both sides of the equation.</u>

−(5x+6)−x=−6−6x

−5x+−6+−x=−6+−6x(Distribute)

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<u>Step 2: Add 6x to both sides.</u>

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8 0
3 years ago
What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?
Sonja [21]

Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.

7x + 3y = 10

↓

\displaystyle\ m= \frac{-7}{-3}

Then you'd simplify.

\displaystyle\ m=\frac{7}{3}

The slope cannot be simplified any more, so this would be the final answer.

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<em>- Marlon Nunez</em>

7 0
3 years ago
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