As far as steps i’ll tell you in the comments
Answer:
The zeros of the function are -0.488 and -7.39
Step-by-step explanation:
Given the quadratic function
f(x) = 2x²+16x-9
The zeros of the function is gotten at when f(x) = 0
2x²+16x-9 = 0
Using the general equation
x = -b±√b²-4ac/2a
From the equation, a = 2, b = 16 and c= -9
x = -16±√16²-4(2)(-9)/2(2)
x = -16±√256-72/4
x = -16±√184/4
x = -16+13.56/4
x = -16+13.56/4 and -16.13.56/4
x = --2.44/5 and -29.56/4
x = -0.488 and -7.39
<span>18x+9xy is correct all Roots are to x=0 and y=-2
(9x⋅2)+(9x⋅y) is correct </span>Roots are to x=0 and y=-2
Since the triangle is equilateral, all its angles are equal to 60°
AO is the bisector⇒∠OAD = 30°
AO AO is the hypotenuse, ∠OAD = 30°⇒
OD=10:2=5ft
By the Pythagorean theorem




Answer: A)
ft²
P.S. Hello from Russia and sorry for my bad english :^)