<em>Your question has confusing details. So, I will rephrase as:</em>
<em>How many 2' x 4' would be needed for Bottom Plates and Double Top Plates on a Building 25' x 50' ?
</em>
<em></em>
Answer:
12.5 plates
Step-by-step explanation:
Given
Building dimension:
Plates
To do this, we have to divide the dimension of the building by the dimension of the plates
So, we have:
and
For the length, we have:
For the width, we have:
So, 12.5 of the plates are needed
2/10 x 2/10 = 4/10 that can be a expression sorry if im wrong
Answer:
11.6--------------------------------------
Explanation:
See the attached image for a visual reference
The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)
We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is
AD = x
Because AD is another radius of the same circle
Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to
11.6 when rounding to the nearest tenth (one decimal place)
Answer:
12
Step-by-step explanation:
Lets c = chord inside circle
3(3 + c) = 6^2
9 + 3c = 36
3c = 27
c = 9
x = 3 + 9
x = 12
Answer:
70
Step-by-step explanation:
Let's say something multiplied by 60 = 4,200
We will represent something with Y
Then,
Y × 60 = 4,200
60Y = 4,200
Divide both sides by 60, then we'll have
60Y/60 = 4,200/60
Y = 4,200/60
Y = 70
Therefore, the other factor is 70