Answer:
1)28.8%
2)28.8%
3)43.6%
Step-by-step explanation:
1))Probability of wining both = Probability that first contract is won* Probability that second contract is won = 0.4 * 0.72 = 0.288 = 28.8%
2)Probability of losing = 1 - Probability of winning
Probability that they will lose both contracts = Probability that first contract is lost * Probability that second contract is lost = (1 - 40/100) * (1 - 54/100) = 0.276 = 27.6%
3)Probability that any one is won = 1 - both contracts are won - both contracts are lost = 1 - 0.276 - 0.288 = 0.436 = 43.6%
Answer:
y = -3
Step-by-step explanation:
{y = x/2 - 4
y = 1 - 2 x
Substitute y = x/2 - 4 into the second equation:
{y = x/2 - 4
x/2 - 4 = 1 - 2 x
In the second equation, look to solve for x:
{y = x/2 - 4
x/2 - 4 = 1 - 2 x
Add 2 x + 4 to both sides:
{y = x/2 - 4
(5 x)/2 = 5
Multiply both sides by 2/5:
{y = x/2 - 4
x = 2
Substitute x = 2 into the first equation:
{y = -3
x = 2
Collect results in alphabetical order:
Answer:
{x = 2
y = -3
Answer:
14
Step-by-step explanation:
The question is asking for the value of A when n = 2
So we just need to plug in 2 for n
A(2) = 10 + (<em>2</em>-1)(4) = 10 + (1)(4) = 10 +4 = 14
Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
What are the questions attach a pic plz