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Anettt [7]
3 years ago
10

Which graph represents the function y = 4?

Mathematics
2 answers:
Zarrin [17]3 years ago
6 0

Answer:

the graph that represents the function y = 4 is A.

Step-by-step explanation:

y = 4 goes across the y-axis

Temka [501]3 years ago
5 0

Answer:

The first one

Step-by-step explanation:

This is a constant function, i.e. the value for y doesn't depend on x. So, every x value will lead to the same y value, in this case 4.

This implies that the graph is a horizontal line, composed by all points like (x,4), where x can be any value and 4 is fixes as the y coordinate.

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Please help me solve question 2
sergiy2304 [10]

Answer:

solution: ( 3 , 6 )

\sf y =6

\sf x =3

Step-by-step explanation:

\sf y = \frac{2}{3} x+4

\sf 2x+3y = 24

make y the subject in equation 2:

\sf 2x+3y = 24

\sf 3y = 24-2x

\sf y = \frac{24-2x}{3}

insert this in equation 1:

\sf \frac{24-2x}{3} =\frac{2}{3} x+4

\sf \sf \frac{24-2x}{3} =\frac{2x+12}{3}

\sf (24-2x) = (2x+12)

\sf -2x-2x=12-24

\sf -4x=-12

\sf x =3

solve for y:

\sf y = \frac{24-2x}{3}

\sf y = \frac{24-2(3)}{3}

\sf y =6

8 0
2 years ago
Read 2 more answers
HELPPPPPPPP MEEEEEEE PLZZZZZZZZ
olga55 [171]
I think it’s the 3rd one
5 0
3 years ago
Simplify: <br> <img src="https://tex.z-dn.net/?f=2%2F5%281%2F3x-15%2F8%29-1%2F3%281%2F2-2%2F3x%29" id="TexFormula1" title="2/5(1
expeople1 [14]

Answer:

16/45x-11/12

Step-by-step explanation:

2/5(1/3x-15/8)-1/3(1/2-2/3x)\\= 2/15x-30/40-1/6+2/9x\\= 16/45x-11/12

3 0
3 years ago
Read 2 more answers
Which function represents the graph of h(x)=2∣∣x+3∣∣−1h(x)=2|x+3|−1 after it is translated 2 units right?
frosja888 [35]
C because i learned it from xxxx xxx
6 0
3 years ago
find the equation of a straight line passing through the point(4,5) and equally inclined to the lines 3x = 4y +7 and 5y= 12x +6
galina1969 [7]
<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:

y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5

The formula to be used in the proceeding steps is    a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting,      a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5)     =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope 

y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
3 0
3 years ago
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