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GuDViN [60]
3 years ago
6

The graph of y = –2x + 11 is:

Mathematics
1 answer:
anastassius [24]3 years ago
7 0
I believe the answer is A, a line that shows only one solution to the equation
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(03.01 MC) The length of a rectangle is 5 units and its width is 4 units. What is the approximate length of the diagonal of the
Alexxandr [17]

Answer:

√41, or about 6.4 units

Step-by-step explanation:

\sqrt{ {5}^{2}  +  {4}^{2} }  =  \sqrt{25 + 16}  =  \sqrt{41}

√41 is about 6.4 units

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1 year ago
Describe the advantages you see in using a rule for a function rather than listing function values in a table.​
Gelneren [198K]

Answer:

Using a rule is direct and not time wasting, which is not the case for listing functions

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3 years ago
Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

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The sum of double a number and 8
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The answer is 10...............
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I don't understand this question please write again

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3 years ago
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