Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D
Therefore also ∡2 = ∡3 (they are half of the congruent angles)
For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.
Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)
T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4
∡AOD = ∡BCD because their measure is the difference of congruent angles.
Answer:
T'(-1, 4), U'(8, 4) and V'(-1, 10)
Step-by-step explanation:
If we reflect the vertices of the given triangle VTU across a line y = 3,
Rule to followed for the image points,
Line of reflection will work as a mirror.
And distance of image points and original points will be same from the line of reflection.
Therefore, Coordinates of the vertices of the image triangle will be,
T'(-1, 4), U'(8, 4) and V'(-1, 10)
Answer: all real numbers that are greater then equal to 2 so (b)