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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!

Mathematics

2 answers:

astraxan [27]3 years ago

4 0

Answer:

The answer is C.

Step-by-step explanation:

Recall that as consequence of the Fundamental Theorem of Algebra, a polynomial of n-th degree has n complex roots (some roots, or all of them, can be real).

Now, as we have a polynomial of degree 5, it has 5 roots. From the statement we know that its graph has three intercepts with the X-axis, which is equivalent to the existence, at least, of three real roots. Moreover, we know that the multiplicity of each root is one. Then, we have exactly three real roots.

The above deduction means that there are other two roots, and those must be complex.

aleksandr82 [10.1K]3 years ago

3 0

Answer: C

<u>Step-by-step explanation:</u>

Degree of 5 means there are 5 roots.

If 3 roots are real, then there are 2 remaining - which must be imaginary.

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(N + 1 )^ 2 for N = -9

Mariulka [41]

Answer: 82

Step-by-step explanation:

(N + 1 )^ 2 for N = -9

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81+1

(-9 +1))^ 2 - Every number raised to power 2 positive your result will be positive

3 0

3 years ago

PLEASE HELP RIGHT AWAY, <br> THANK U SO MUCH!! <3

vredina [299]

Answer:

1. Ans;

${a}^{7} \times {a}^{12} = {a}^{7 + 12} = {a}^{19}$

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2. Ans;

$\frac{ {h}^{6} }{ {h}^{2} } = {h}^{4}$

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3. Ans;

${e}^{6} \times {e}^{6} = {e}^{6 + 6} = {e}^{12}$

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4.Ans;

$\frac{ {w}^{9} }{ {w} } = {w}^{8}$

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5. Ans;

${g}^{2} \times {h}^{3} \times {g}^{2} \times h = {g}^{2 + 2} \times {h}^{3 + 1} = {g}^{4} {h}^{4}$

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6.Ans;

$\frac{10 {a}^{12} }{ 6{a}^{3} } = \frac{5 {a}^{9} }{3}$

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7.Ans;

$({m}^{4} )^{5} = {m}^{4 \times 5} = {m}^{20}$

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8.Ans;

${(3 {a}^{2} })^{3} = ( {3})^{3} ( {a}^{2} ) ^{3} = 27 {a}^{6}$

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9.Ans;

${( \frac{c}{k} })^{4} = \frac{ {c}^{4} }{ {k}^{4} }$

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10.Ans;

${( \frac{8x}{9} })^{2} = \frac{( {8x})^{2} }{ ({9})^{2} } = \frac{64 {x}^{2} }{81}$

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11.Ans;

$4 {c}^{2} \times {c}^{3} = 4 {c}^{2 + 3} = 4 {c}^{5}$

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12.Ans;

${( - 9 {h}^{4} {k}^{6} })^{2} = {( - 9)}^{2} {( {h}^{4} })^{2} {( {k}^{6} })^{2} = 81 \: \: {h}^{8} {k}^{12}$

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13.Ans;

$( { \frac{2d}{3e} })^{3} = \frac{ {(2d)}^{3} }{ ({3e)}^{3} } = \frac{8 {d}^{3} }{27 {e}^{3} }$

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14. Ans;

${( \frac{4}{ {w}^{5} }) }^{3} = \frac{ ({4)}^{3} }{( {w}^{5} ) ^{3} } = \frac{64}{ {w}^{15} }$

_____o___o_____

$\frac{5 {v}^{4} \times 4 {v}^{5} }{2 {v}^{3} } = \frac{20 {v}^{4 + 5} }{2 {v}^{3} } = \frac{20 {v}^{9} }{2 {v}^{3} } = 10 {v}^{6}$

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$( \frac{3 {f}^{4}h}{4 {h}^{9} } ) ^{3} = \frac{( {3})^{3} ( {f}^{4})^{3} ({h})^{3} }{ {(4)}^{3} ( {h}^{9})^{3} } \\ \\ \\ = \frac{27 {f}^{4 \times 3} {h}^{3} }{64 {h}^{9 \times 3} } = \frac{27 {f}^{12} {h}^{3} }{64 {h}^{27} } \\ \\ \\ = \frac{27 {f}^{12} }{64 {h}^{24} }$

I hope I helped you^_^

5 0

3 years ago

The solution for 7(5x+9)=12-(x+9) and simplified

Charra [1.4K]

Answer:

x= -5/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7(5x+9)=12−(x+9)

7(5x+9)=12+−1(x+9)(Distribute the Negative Sign)

7(5x+9)=12+−1x+(−1)(9)

7(5x+9)=12+−x+−9

(7)(5x)+(7)(9)=12+−x+−9(Distribute)

35x+63=12+−x+−9

35x+63=(−x)+(12+−9)(Combine Like Terms)

35x+63=−x+3

Step 2: Add x to both sides.

35x+63+x=−x+3+x

36x+63=3

Step 3: Subtract 63 from both sides.

36x+63−63=3−63

36x=−60

Step 4: Divide both sides by 36.

36x/36 and -60/36

x= -5/3

4 0

4 years ago

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Answer:

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6 0

4 years ago

Explain which variables would be included when using technology to calculate the present value of a lump sum and to calculate th

koban [17]

Answer:

a. Present value of a lump sum =

PV = FV / ( 1 + i )ⁿ

b. Present value of an annuity =

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ )) / r)

Step-by-step explanation:

a. Present Value of a Lump sum =

PV = FV / ( 1 + i )ⁿ

Where variables in the formula are explained as follows

PV = Present Value of the given amount today

FV = Future Value of the given amount

i = Discount rate

n = Number of periods

b. Present value of an annuity is given as:

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ)) / r)

The variables in the equation are explained as the follows:

P = the present value of annuity

PMT = Payment per period or the amount in each annuity payment

r = the interest or discount rate

n = total number of periods or the number of payments left to receive

8 0

4 years ago