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Sonbull [250]
3 years ago
12

Which statement holds true for a skewed histogram showing a distribution of the weights of students in a class?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0
Among the choices, the statement which describes a skewed histogram showing a distribution of the weights of students in a class is:

<span>"The nature of the skew can be verified by the position of the mean with respect to the mode."

The histogram is skewed to the right if the mean is less than the mode and the histogram is skewed to the left if the mean is more than the mode. </span><span />
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150% of $22 (math test)
Rom4ik [11]

Answer:

6.8181818

Step-by-step explanation:

3 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
You want to know how many miles harriet went. which situation about her exercise best represents the inequality 15x 7 &gt; 52?
Lady_Fox [76]
The answer is either a or d but we know she did all of this for more than 52 minutes.
8 0
3 years ago
What is the value of x in the figure? (2x+15)°
Deffense [45]

Answer:

(2x + 15)° = 180°

2x = 180 - 15

2x = 165

x = 165/2

x = 82.5

6 0
3 years ago
Please solve!!!<br> Will name the Brailiest!
kiruha [24]

Answer:

So to graph using a table, the first step is...well... make a table. so you have a column of x and y. under the x column write down a bunch of values you would like to test. I am going to test -2 through 2.

x | y

-2|

-1|

0 |

1 |

2 |

 

Next, we have to plug each of those values into the equation y=2x to see what the corresponding y value is.

when x=-2 y=2(-2)=-4, when x=-1 y=2(-1)=-2, and so on...

x | y

-2|-4

-1|-2

0 |0

1 |2

2 |4

 

Next, graph those points on a coordinate plane. Each row on the table is a point on the graph, (x,y).  Hope that helps!

7 0
2 years ago
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