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zysi [14]
3 years ago
11

Simplify: 1. Write the prime factorization of the radicand. 2. Apply the product property of square roots. Write the radicand as

a product, forming as many perfect square roots as possible. 3. Simplify. =

Mathematics
2 answers:
Elis [28]3 years ago
4 0

Simplify: 

<span>1. Write the prime factorization of the radicand.</span>  <span>2. Apply the product property of square roots. Write the radicand as a product, forming as many perfect square roots as possible. </span>

3. Simplify.

 =the answer is 18


KonstantinChe [14]3 years ago
3 0

Here's the answer to something that won't let me copy and paste the question. Ur welcome.


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Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

<u><em>5*[∫x^{2}dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>

<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

4 0
3 years ago
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