Notes separated by a perfect fifth have a frequency ratio of 3:2.
The frequency of the note a perfect fifth below B3 will be
246.94×2/3 = 164.62667
The appropriate choice is ...
164.63 Hz
For this case we have the following expression:

For power properties we have:

Rewriting the exponents of the expression we have:



Using the cubic root we have:
![(\frac{1}{\sqrt[3]{8^2}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B8%5E2%7D%7D%20a%5E2%29%20%20%20)
![(\frac{1}{\sqrt[3]{64}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B64%7D%7D%20a%5E2%29%20%20%20)
![(\frac{1}{\sqrt[3]{4^3}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B4%5E3%7D%7D%20a%5E2%29%20%20%20)
Simplifying the expression we have:

Answer:
The equivalent expression is given by:

Answer: go to google and use a calculater
Step-by-step explanation:
Answer:
Step-by-step explanation:
We can write the equation using the point and the slope .
Formula we need to use is the point slope formula
Which is given by
Y-y1= m(X-x1)
Here given that (x1,y1)=(1,-1) and m = -3
x1= 1
y1 = -1
so equation is
Y-(-1) = -3 (x-1)
Distribute the slope
y+1 = -3x+3
y= -3x+3-1
y = -3x + 2
So the equation is
y =-3x +2