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3 years ago

I NEED HELP ASAP! THANKS :)

Mathematics

2 answers:

kirill [66]3 years ago

6 0

Answer:

Option B

Step-by-step explanation:

Alborosie3 years ago

5 0

Answer:

$35\sqrt[5]{49}$

Step-by-step explanation:

I simply plugged it into my calc and solved it.

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Rena wrote all the integers from 1 to 12. <br><br> How many numbers did she write?

Aleksandr [31]

Answer:

integers from 1 to 9 have only one number each, so in total 9 numbers. integers from 10 to 12 have 2 numbers each, 3*2=6. 9+6=15

7 0

3 years ago

Read 2 more answers

Given a line segment containing the points A,B, & C, in order, if AB is 11 and BC is 12, then the length of AC would

Shalnov [3]

Answer: 23

Step-by-step explanation:

AB + BC = AC

AC = 11 + 12 = <u>23</u>

4 0

2 years ago

A drainage pipe 66 in. tall measures 25.12 in. around.

Schach [20]

In order to solve this using V= B(h) (The B is area of the base) you need a radius it doesn't give us that but it does give us the circumference.
C= 3.14(2r)
25.12=2r divide each by 2
12.56=r
now use this in the volume formula:
V= 12.56^2(3.14)(66)
V=32,692.86 cubic inches

8 0

4 years ago

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

1 year ago

How much does each one equal?

nadya68 [22]

Answer:

need more information

4 0

3 years ago