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jok3333 [9.3K]
2 years ago
12

Assume that the variable U represents a positive real number

Mathematics
1 answer:
lisov135 [29]2 years ago
3 0

Answer:

Step-by-step explanation:

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Given six consecutive integers with a sum of seven times the
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Answer:

<em>x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)</em>

Step-by-step explanation:

<u>Equations</u>

The situation can be written as an algebraic equation by setting the variables as follows:

x = first integer

x + 1 = second integer

x + 2 = third integer

x + 3 = fourth integer

x + 4 = fifth integer

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3 years ago
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aleksklad [387]

Answer:

<u>Question 3</u>

Given expression:

\sf \left(\dfrac{-8}{9} \times \dfrac{1}{-5}\right)+\left(\dfrac{-8}{9} \times \dfrac{-7}{11}\right)

Both parentheses share a common term.

To factor out a common term: ab + ac = a(b + c)

\textsf{Factor out the common term }\dfrac{-8}{9}

\sf \implies\dfrac{-8}{9} \times \left(\dfrac{1}{-5}+\dfrac{-7}{11}\right)

-------------------------------------------------------------------------------------------------

<u>Question 4</u>

To calculate the amount of money Rajni had to begin with, sum the three amounts she spent:

\sf \implies total=10\frac14+25\frac34+16\frac12

As \sf a\frac{b}{c}=a+\frac{b}{c}, then:

\sf \implies 10+\frac14+25+\frac34+16+\frac12

Collect and sum the whole numbers:

\sf \implies (10+25+16)+\frac14+\frac34+\frac12

\sf \implies 51+\frac14+\frac34+\frac12

As  \sf \frac14+\frac34=\frac44=1, then

\sf \implies 51+1+\frac12

\sf \implies 52+\frac12

\sf \implies 52\frac12

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