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MA_775_DIABLO [31]
3 years ago
15

A basket contains 8 green apples, 11 red apples, 5 nectarines, and 12 oranges. Mark randomly chooses a piece of fruit, eats it,

then selects another. Find P(a green apple then a nectarine)
Mathematics
1 answer:
bogdanovich [222]3 years ago
3 0

Answer:

3.17% probability of selecting first a green apple and then a nectarine.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

P(a green apple then a nectarine)

This is the probability of selecting first a green apple and then a nectarine.

Initially, there are 8+11+5+12 = 36 fruits, of which 8 are green apples. So 8/36 probability of choosing a green apple.

Now, there are 35 fruits, of which five are nectarines. So 5/35 probability of choosing a nectarine.

Then

p = \frac{8}{36}\times\frac{5}{35} = 0.0317

3.17% probability of selecting first a green apple and then a nectarine.

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