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Flura [38]
3 years ago
5

Anybody bother to help???

Mathematics
1 answer:
Dovator [93]3 years ago
5 0
Idk about number 4 but I think the other ones are correct

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A baseball player throws a ball from second base to home plate. How far does the player throw the ball?
Fynjy0 [20]

Answer:

The player throws 127.3 ft from second base to home plate.

Step-by-step explanation:

Given:

Distance from home to first base = 90 ft

Distance from first base to second base = 90 ft

We need to find the distance from second base to home.

Solution:

Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.

Now by using Pythagoras theorem which states that;

Square of the hypotenuse side is equal to sum of squares of other two sides.

framing in equation form we get;

distance from second base to home = \sqrt{90^2+90^2}= 127.27 \ ft

Rounding to nearest tent we get;

distance from second base to home = 127.3 ft

Hence The player throws 127.3 ft from second base to home plate.

6 0
3 years ago
5/8 divided by 1 1/3? In fraction form
Rom4ik [11]

Answer:

15/32

Step-by-step explanation:

3 0
2 years ago
Calculate the angle of a sector of 50° and a radius of 4cm
Anastasy [175]

Answer: 20π/9 cm²

Step-by-step explanation:

Central angle is given as = 50°

We should note that for a complete circle to be made, it needs 360∘. Therefore, this is 50/360 = 5/36 of the area of a sector.

Area of the sector = 5/36 × πr².

= 5/16 × π × 4²

= 5/36 × π × 16

= 80π/36

= 20π/9 cm²

7 0
2 years ago
At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
V125BC [204]

Answer:

\frac{^3C_1\times ^4C_1}{^{12}C_2}

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = ^3C_1\times ^4C_1

Also, the total combination of choosing any 2 subjects out of 12 subjects = ^{12}C_2

Hence, the probability that a student chooses an art elective and a history elective = \frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}

=\frac{^3C_1\times ^4C_1}{^{12}C_2}

Which is the required expression.

3 0
3 years ago
Read 2 more answers
Can someone please help me with atleast one and explain how to do it
Anna [14]
There's a couple ways to do this. These look like special triangles to me. Which should be the 30 60 90 triangle's which have the same ratios for their legs. The legs will always be square root three and one and the hypotenuse of two - I can't see what I'm typing for some reason so I will finish in a comment
3 0
3 years ago
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