Given:
The table of values of an exponential function.
To find:
The decay factor of the exponential function.
Solution:
The general form of an exponential function is:
...(i)
Where, a is the initial value and 
is the decay factor and 
is the growth factor.
The exponential function passes through the point (0,6). Substituting 
in (i), we get
The exponential function passes through the point (1,2). Substituting 
in (i), we get
Here, 
lies between 0 and 1. Therefore, the decay factor of the given exponential function is 
.
Hence, the correct option is A.
Answer:
D is correct option.
Step-by-step explanation:
We are given a function 
We need to find new function reflection of f(x) across the y-axis.
When function reflection across y-axis 
Therefore, 
New function, 
Thus, D is correct option.
Answer:
200.4 at 0.25%
Step-by-step explanation:
Given data
P= P200
r= 0.25%
t= 1 year
n= 12
A= P(1+ r/n)^nt
substitute
A= 200(1+ 0.0025/12)^12*1
A= 200(1+ 0.00020833333)^12
A= 200(1.0002)^12
A= 200* 1.002
A= 200.4
Hence the amount is 200.4 at 0.25%
Given the following data set 2,3,1,6,1,1,1,0,2,4,5,1,2,2,3<br>Mean <br>Median <br>Range<br>Mid range
igomit [66]
Answer:
mean: 34/15=2.27
median: 2
range: highest-lowest...... 6-0=6
mid range: high + low divided by 2
6+0=6/2=3
2x⁴+17x²+8
Let X = x² →→(x = + or -√X )
The quadratic becomes : 2.X² + 17.X + 8. Now solve for X:
X' = [-b+√(b²-4ac)]/2a and X" = [-b-√(b²-4ac)]/2a
Plug I the values of a, b and c and you will find;
X' = -1/2 and X" = - 8
Since X = √x → →X' = √( -1/2) [imaginary roots]
and X" = √-8 →→ X" = 2√-2 [imaginary roots]
Then:
1st ROOT: X' = - √1/2.i
2nd ROOT: X" = + √1/2.i
3rd ROOT: X" = + 2√2.i
4th ROOT: X" = - 2√2.i
