Question

If x+y=3 and xy=2 find the value of x^2+y^2​

Answer 1

Answer:

yes but something like that

Answer 2

Answer:

5

Step-by-step explanation:

We know that

$x + y = 3$

and

$xy = 2$

Solve for x in first variable

$x = 3 - y$

Substitute this into second equation

$(3 - y)y = 2$

$- {y}^{2} + 3y - 2$

Simplify

${y}^{2} - 3y + 2$

$(y - 1)(y - 2)$

$y = 1$

$y = 2$

So x or y can be

$x = 1 \: \: y = 2$

or

$x = 2 \: \: \: y = 1$

So we need to find x^2 and y^2.

${2}^{2} + {1}^{2} = 5$