Answer:
D
Step-by-step explanation:
Given the quadratic
d = - 16t² + 12t ← subtract d from both sides
- 16t² + 12t - d = 0 ← in standard form
with a = - 16, b = 12, c = - d
Use the quadratic formula to solve for t
t = ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 4
) / - 32
= 
± 
= 
± 
= ± 
→ D
Y=ax+b, y=cx+d (a≠0, c≠0)
If the two line cross perpendicularly ⇔ ac= -1
So a tangent of the perpendicular line is "-(1/5)".
Then, the equation of the perpendicular line is y=-(1/5)x+a (a is <span> y-intercept</span>).
On the other hand, this equation pass r(1, 3), so
3 = -(1/5) times 1 + a
∴ a=16 / 5
Therefore, y=-(1/5)x+16 /5 is answer.
By the way, I'm Japanese so if you find some mistakes in my English, please let me know.
So the equation of the red graph is already given to us: 
. I assume you meant the blue graph?
We can use the vertex form: 
, where 
is the vertex. (We can ignore 
because is 1 for this graph.) Remember that the vertex is the maximum or minimum of a parabola and the point that the line of symmetry passes through. For f(x) the vertex is (0,0).
The vertex for 
is at 
on the coordinate plane. (4 left, 2 down)
Plug into the vertex form:
The double negative becomes a positive, and then you're done:
Answer:
Step-by-step explanation:
For the first triangle
y=160
x= 111
For the second triangle
x= 53
y= 70
For the other question on the bottom
19.8
2:16
2.5:20
3:24
4:32
5:40
1.5:12
