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3 years ago

Which has the lowest unit price ?

Mathematics

2 answers:

iren2701 [21]3 years ago

6 0

Answer:dd

Step-by-step explanation:d

11111nata11111 [884]3 years ago

5 0

Answer:

The answer is $0.33 for 11 oz

Step-by-step explanation:

All you have to do is divide the oz by the price and A is the lowest.

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I need help with this question

kirill115 [55]

Answer:

PART A:

PETER

PART B:

GIWA

PART C:

WEEK 10

Step-by-step explanation:

PART A:

Peter saves $10 every week why GIWA saves $10 every two weeks making it $5 every week.

PART B:

GIWA started with more money. He started with $ 70 why Peter started with $20

PART C:

They both had $120 in the tenth week

5 0

3 years ago

Taylor uses 1/8 pound of chocolate in every cookie recipe she makes. If she used 3/4 pound of chocolate yesterday, how many batc

omeli [17]

She made 6 patches of cookies because if she uses 1/8 per batch and 3/4 x2 equals 6/8 , she made 6 batches.

7 0

2 years ago

Read 2 more answers

Factor the expression completely.

evablogger [386]

Answer:

Factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

Step-by-step explanation:

We need to factor the expression $xy^4+x^4y^4$ completely

We need to find common terms in the expression.

Looking at the expression, we get $xy^4$ is common in both terms, so we can write:

$xy^4+x^4y^4\\=xy^4(1+x^3)$

So, taking out the common expression we get: $xy^4(1+x^3)$

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So, we get:

$xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)$

Therefor factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

6 0

3 years ago

1. What percent of 600 is 12?

Ainat [17]

Answer:

Step-by-step explanation:

Set up a proportion

x / 100 = 12 / 600

Cross multiply

600x = 1200

Divide both sides by 600

x = 2

I hope this helped and please mark me as brainliest!

4 0

2 years ago

Read 2 more answers

Solve for x when <img src="https://tex.z-dn.net/?f=x%5E%7Byz%7D%20%3Dy%5E%7B2%7D" id="TexFormula1" title="x^{yz} =y^{2}" alt="x^

Assoli18 [71]

The value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

<h3>How to solve for x?</h3>

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

$x^{yz} = y^2$

Take the yz root of both sides

$\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}$

Apply the law of indices

$x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}$

Divide yz by yz

$x = \sqrt[yz]{y^2}$

Hence, the value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$