Answer:
2 imaginary roots
Step-by-step explanation:
The discriminate is the portion of the quadratic equation under the square root
D = b^2 - 4ac
D = 8^2 - 4(2)(16)
D = 64 - 128
D = -64
Since the discriminate is negative the square root will be imaginary
and there will be 2 of them
2 imaginary roots
Answer:
y = x/2 - 7
Step-by-step explanation:
First, we need to find the slope of the given equation: x - 2y = 8
Subtract x from both sides
x - 2y = 8
- x - x
-2y = 8 - x
Divide both sides by -2
-2y/-2 = (8 - x)/-2
y = -4 + x/2
The slope of this equation is 1/2
So the equation of our parallel equation is y = x/2 + b
We have to find b, so plug in the given coordinates
-6 = 2/2 + b
-6 = 1 + b
Subtract 1 from both sides
-6 = 1 + b
- 1 - 1
b = -7
Plug it back into the original equation
y = x/2 - 7
If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3.
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two.
Keith = x
Troy = x-3
Joe = 2(x-3)
Answer:
The coordinates of the image of vertex P after reflection is (-7, 4)
Step-by-step explanation:
Given that we are to reflect the point P across the x-axis, we have;
Reflection of a point across the x-axis gives;
When a point is reflected across the x axis, the y-coordinate changes to the opposite sign while the x-coordinate remains unchanged such that (x, y) becomes (x, -y)
Therefore, given that the point P = (-7, -4), we have;
Coordinates of point P before reflection Reflection = (-7, -4), coordinates of point P after reflection Reflection P' = (-7, 4).
