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3 years ago

Does any one know this i need help!!!

Mathematics

1 answer:

Ber [7]3 years ago

5 0

Answer:

7(x)=5x+7

to find the x / zero intercept, plug in f (x) = 0

0=5x+7

move the left side and change the sign

-5x7

divide both of the equation by -5

x= $-\frac75$

same steps for g(x)=-2x-4

x=-2

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The scheduled commuting time on the Long Island Railroad from Glen Cove to New York City is 65 minutes. Suppose the actual commu

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3 years ago

Find the 43rd term of the sequence<br><br> -3.0,-2.5,-2.0,-1.5

Nana76 [90]

Answer:

19.5

Step-by-step explanation:

The 43rd term of the sequence is 19.5

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3 years ago

Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria?Tem

Xelga [282]

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

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3 0

3 years ago

AAA Packages Plus sends packages overnight for $5 plus $0.25 per ounce. United Packages charges $2 plus $0.35 per ounce.

Nata [24]

A.)
The equation for AAA packages plus would be .25x+5
The equation for United packages would be
.35x+2

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7 0

3 years ago

Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz

klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0

3 years ago

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