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kotykmax [81]
4 years ago
12

The two triangles below are similar. Which pair are corresponding sides?

Mathematics
2 answers:
velikii [3]4 years ago
3 0
MN and QR are corresponding :-)
kondaur [170]4 years ago
3 0

Answer:

2) MN correspond to QR .

Step-by-step explanation:

Given : The two triangles below are similar.

To find : Which pair are corresponding sides

Solution : We have given that Triangle LMN is similar to triangle PQR.

Then Sides

MN correspond to QR .

Therefore, 2) MN correspond to QR .

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Claire has $210 to spend on clothes. She wants to buy a pair of shorts and some shirts. The cost of a pair of shorts is $25, and
Komok [63]

Answer:

discount of 50% on one shirt, which inequality can be used to find the maximum number of shirts, n, that she can buy?

Step-by-step explanation:

has $210 to spend on clothes. She wants to buy a pair of shorts and some shirts. The cost of a pair of shorts is $25, and the cost of a shirt is $40. If she gets a discount of 50% on one shirt, which inequality can be used to find the maximum number of shirts, n, that she can buy?

3 0
4 years ago
Trigonometric question, 30 points, will give brainliest.
zheka24 [161]

hmmm first off let's convert the √3 +i to trigonometric form, and then use De Moivre's root theorem, bearing in mind that √3 and i or 1i are both positive, meaning we're on the I Quadrant.

\bf (\stackrel{a}{\sqrt{3}}~,~\stackrel{b}{1i})\qquad \begin{cases} r=&\sqrt{(\sqrt{3})^2+1^2}\\ &\sqrt{3+1}\\ &2\\ \theta =&tan^{-1}\left( \frac{1}{\sqrt{3}}\right)\\\\ &tan^{-1}\left( \frac{\sqrt{3}}{3} \right)\\ &\frac{\pi }{6} \end{cases}~\hfill \implies ~\hfill 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right]

\bf ~\dotfill\\\\ \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] ~\dotfill

\bf \left[ 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right] \right]^3\implies 2^3\left[ cos\left( 3\cdot \frac{\pi }{6}\right) +i~sin\left( 3\cdot \frac{\pi }{6}\right) \right] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 8\left[cos\left( \frac{\pi }{2} \right) +i~sin\left( \frac{\pi }{2} \right) \right]~\hfill

3 0
4 years ago
Answers are <br> (-1,3) <br> (0,2)<br> (1,2)<br> (2,-1)<br> (2,2)
sladkih [1.3K]
DahiaizmdmekwoOkxndjsoao1,2
7 0
3 years ago
Ten times a number increased by 150
timama [110]

Hey there!

"A number" is referred to an unknown number so we can say it is labled as

x

"Increased" means you're going up/ adding

ten = 10

150 stays the same

"Ten times a number" =

\bf{10x}

"Increased by 150" =

\bf{ + 150}

Thus your answer should look like this:

\bf{10x + 150}

Good luck on your assignment and enjoy your day!

~

\frak{loveyourselffirst }

3 0
3 years ago
Complete the sentence.
melamori03 [73]

Please view my other solution I gave you.

:)


But I will still answer this if you see it.

Because 0.8^x is never 0, then the asymptote is 0-10 or -10.

6 0
3 years ago
Read 2 more answers
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