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Marrrta [24]
3 years ago
10

Can someone please help ? Factor. 10x^5+5x^2−15

Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer:

5(2x^5 + x^2 - 3)

Step-by-step explanation:

The only factor in common is 5, so you would have 5(2x^5 + x^2 - 3). That can't be factored further. IF the equation had been to the fourth degree on the first term rather than to the fifth degree, it could have been factored as 5(2x^2 -3)(x^2 +1).

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A parabola is graphed such that the axis of symmetry is x = 3. One of the x-intercepts is (5, 0). What is the other x-intercept?
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The axis of symmetry is the fold line that splits the parabola down the middle.

Now, since a parabola is symmetrical, every point, except the vertex, will have a mirror image of another point if we folded the parabola over the axis of symmetry.

So if we know the axis of symmetry is x = 3 and one of our points

has the coordinates (5, 0), the other point will have the coordinates (3, 0).

The axis of symmetry is always halfway between the x-intercepts.

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3 years ago
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amm1812

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2 years ago
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Find x such that x - 4, x, and 3x - 8 are three consecutive terms in a geometric sequence
Nitella [24]
In a geometric sequence dividing any term by the term before it yields the common multiplier.
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You can buy 10 pounds of melons
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