All categories

3 years ago

Can someone please help ? Factor. 10x^5+5x^2−15

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Answer:

5(2x^5 + x^2 - 3)

Step-by-step explanation:

The only factor in common is 5, so you would have 5(2x^5 + x^2 - 3). That can't be factored further. IF the equation had been to the fourth degree on the first term rather than to the fifth degree, it could have been factored as 5(2x^2 -3)(x^2 +1).

You might be interested in

. Una persona desea realizar una pintura para su próxima exposición en donde esta tenga tres colores fluorescentes y dos colores

ycow [4]

Answer: B. 350.

Step-by-step explanation:

Given: Total number of fluorescent colors = 7

Total number of pastel colors = 5

Since , he want three fluorescent colors and two pastel colors.

Number of ways to select r things out of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Number of ways to choose colors = $^7C_3\times\ ^5C_2$

$=\dfrac{7!}{3!4!}\times\dfrac{5!}{2!3!}\\\\=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}\times\dfrac{5\times4\times3!}{2\times3!}\\\\=350$

Hence, the correct option is B. 350.

3 0

2 years ago

Rosie wants to make a cube with rectangular blocks each measuring 6cm by 3cm by 8cm. Find the least number of blocks she must us

Marysya12 [62]

Hello,

lower commun multiple(3,6,8)=24 (blocks)
================================

4 0

2 years ago

GIVE ME A REAL ANSWER PLEASE! IT IS DUE NOW! Factor completely 3x^2 + 5x + 1.

Elena L [17]

Answer:

prime

Step-by-step explanation:

3x^2 + 5x + 1

it can't be factorizes with rational numbers

3 0

3 years ago

Read 2 more answers

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

3 years ago

Find the domain and range of the<br>function y = f(x)= √x-2<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%202%7D%20" i

Over [174]

Answer:

3x-x+2=4

Step-by-step explanation:

The domain of f(x)=2^x would be the x values. This would include all values that you can input as x in order to make this problem work. The domain of a function is usually all real numbers. The range of f(x)=2^x would be the y values. This would include all values that would be the output for the y value. An example of this would be if you used 2 as x then the function would read f(x)=2^2. The y would equal 4 which would be included in the range of this function. To find the domain and range of the inverse you would follow the proper steps to get the inverse of the function which would be x=2^y. The domain would be the x values and the range would be the y values. If you put 4 as x which would be your input for the domain you would get 2^4 = 16 for the y which would be the range.

4 0

2 years ago