20/15=N/27
Do cross multiplication.
20x27=540
540/15=39
So the answer ia 39.
Both point (5,12) and (11,12) lie on the horizontal line y=12.
If these two points is a leg of the triangle, the other leg must be perpendicular to the horizontal line, that is, the other leg must be vertical, but passing through either (5,12) or (11,12), i.e. lies on either the vertical line x=5 or x=11.
There is only one point that passes through x=11, i.e. point A(11,4).
You'll need to isolate 9a on the left side of this equation
Please add 7 to both sides of the eqn, obtaining 9a = 117.
Solve for a by dividing both sides by 9: a = 117/9 = 13 (answer)
Answer: r=-3
Step-by-step explanation:
12-6r=2r+36
12=8r+36
-24=8r
r=-3
