$350 at 3% for 10 years whats you account balance

A random sample of 121 students from the University of Oklahoma had a sample mean ACT score of 23.4 with a sample standard devia

Grace [21]

Answer:

(22.74,24.06) is the required 95% confidence interval for the population mean ACT score of University of Oklahoma students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 121

Sample mean = 23.4

Sample standard deviation = 3.65

Level of significance = 0.05

Degree of freedom

$= n - 1 = 120$

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Calculation of critical value:

$t_{critical}\text{ at degree of freedom 120 and}~\alpha_{0.05} = \pm 1.9799$

Putting the values, we get,

$23.4\pm 1.9799(\dfrac{3.65}{\sqrt{121}} )\\\\ = 23.4 \pm 0.6569\\\\ = (22.7431 ,24.0569)\approx (22.74,24.06)$

(22.74,24.06) is the required 95% confidence interval for the population mean ACT score of University of Oklahoma students.

5 0

3 years ago

for an interview 60% of the applicants were selected. After the interview 20% for those who were selected go to the job offer

Y_Kistochka [10]

Answer:

20%

that should be the answer to the question

5 0

2 years ago

27. The average hourly wage of workers at a fast food restaurant is $7.25/hr

morpeh [17]

Answer:

0.0668 = 6.68% probability that the worker earns more than $8.00

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.

This means that $\mu = 7.25, \sigma = 0.5$

If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?

This is 1 subtracted by the pvalue of Z when X = 8. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 7.25}{0.5}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the worker earns more than $8.00

8 0

2 years ago

Please bros, I need this.

Lady_Fox [76]

<span>The answer is It represents a nonlinear function because its points are not on a straight line.</span>

7 0

3 years ago

Read 2 more answers

Graph the line -1 passing through the point (-4,5)

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

If you want to find the equation of line with a given a slope of which goes through the point (-4,5), you can simply use the point-slope formula to find the equation:

---Point-Slope Formula---

where is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)

Distribute

Multiply and to get

Add -1 to both sides to isolate y

Combine like terms and to get the answer

So the equation of the line with a slope of which goes through the point (-4,5) is:

which is now in y=mx = b form where the slope is m=-4/5 and the y-intercept is b=1

6 0

2 years ago