It's False; an octagon has 8 vertices. When you remove the starting vertex and the two adjacent vertices we're left with 5 possible diagonals
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Answer:
- 13 ft
- (a) 1 second; (b) t = 0, t = 1/2
Step-by-step explanation:
<h3>1. </h3>
Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...
5² +(w -1)² = w²
w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms
26 = 2w . . . . . . . . . . . . add 2w
13 = w . . . . . . . . . . . . divide by 2
The length of the wire is 13 feet.
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<h3>2. </h3>
(a) When h = 0, the equation is ...
0 = -16t^2 +8t +8
Dividing by -8 puts this into standard form:
2t^2 -t -1 = 0
Factoring, we get ...
(2t +1)(t -1) = 0
The positive value of t that makes a factor zero is t = 1.
It will take 1 second for the gymnast to reach the ground.
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(b) When h = 8, the equation is ...
8 = -16t^2 +8t +8
Subtract 8 and divide by 8 to get ...
0 = -2t^2 +t
0 = t(1 -2t) . . . . factor out t
Values of t that make the factors zero are ...
t = 0
t = 1/2
The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.
Answer:
10 months
Step-by-step explanation:
my answer is 10 months because i added 30 and 18 together to get 1.6666666666666667 then i divided by 6, because i added 1 and 5 together, and got 10.
Answer:
15 seconds
Step-by-step explanation:
How did i get this answer? It is apparent that the girl is capable of running 6 2/3 metres per one second and she must run 100 metres.
First, let's convert 2/3 into a decimal so that it is easier to calculate later. 2/3=0.667 (you can also just do 2 divide by 3 and will end up with the same number)
Now our numbers are 6.667 and 100. Let's divide 100 by 6.667 which estimates to 15
Answer:
the graph curve will goes above f(x)=x^2.f(x)=3*x^2 curve will also give higher value same value of x .
Step-by-step explanation: