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Andre45 [30]
3 years ago
7

Y=4x^2+7x vertex form

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0
Use completing the square:

Ex:
y = x^2 +4x  \\  \\ y= x^2 +4x +(\frac{4}{2})^2- (\frac{4}{2})^2 \\  \\ y = (x^2 +4x+4) - 4 \\  \\ y = (x+2)^2 - 4

Now apply to your problem.
First factor out the '4' in front of the 'x^2' term
y = 4(x^2 + \frac{7}{4}x)
Apply completing the square:
y = 4(x^2 + \frac{7}{4}x +(\frac{7/4}{2})^2 -(\frac{7/4}{2})^2) \\  \\ y = 4[(x^2 + \frac{7}{4}x+\frac{49}{64}) - \frac{49}{64} ] \\  \\ y = 4(x + \frac{7}{8})^2 - \frac{49}{16}
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The number of members in the recycling club increased by 15 people. If the club had 12 members previously, what was the percent
ivolga24 [154]

Answer:

125%

Step-by-step explanation:

You divide 15 by 12 and convert to a percentage.

Brainliest?

4 0
3 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
What transformation transforms (a, b) to (a, −b)​?
koban [17]

We are given

(a, b) ---------------> (a, −b)​

we can see that

x-values of both points are 'a'

which is same

while y-value of first =b

y-value of second =-b

so, y becomes as -y

and we know that

when a function is reflected about x-axis

then y becomes -y

so, option-C.................Answer

3 0
3 years ago
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12. Uche bought two books at A125 each. She was
liraira [26]
The answer is D N750
4 0
3 years ago
An art gallery is increasing the asking price of its paintings by 60%. A painting now costs $400.00. How much was the painting b
Lera25 [3.4K]
The goal here is to find the cost of the painting BEFORE the 60% increase.

To find the cost of the painting, we must take in the information we already have:

Increase percent: 60%
Original price: unknown
Price after increase: $400

$400 is the price of the painting AFTER the increase has been added. So this equals the cost of the painting before the increase, plus the total amount of the increase (which is 60% of the original price).

The total must be (100% + 60% = 160%) 160% of the original painting price.

To find the original price, we must divide the increased price by the new percentage (160%). But how do we get here?

Well, we have 160% and our (fraction) $400/1%. We will have to switch the 160% and the 1%, giving us..

1% $400/160%

We take 400/160, which is 2.5. But this is only 1% of the original price! We want 100%.

So now, we multiply the 2.5 by 100 to get our answer: $250.

I hope this helps! If you have any questions, feel free to ask.
5 0
3 years ago
Read 2 more answers
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