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andriy [413]
3 years ago
5

As part of a school contest, Sarah and Luis are playing a math game. Sarah must pick a number between 1 and 50 and give Luis clu

es so he can write an equation to find her number. Sarah says, "If i subtract 5 from my number, multiply that quantity by 4, and then add 7 to the result, i get 35." What equation can Luis write based on Sarah's clues and what is Sarah;s clues and what is is Sarah's number?
Mathematics
2 answers:
RSB [31]3 years ago
8 0
Simple, writing an equation,

(x-5)*4+7=35

multiply the 4 in

4x-20+7=35

4x-13=35

add 13 to the other side

4x-13=35
     +13  +13
4x=48

x=12.

The number is 12. But to check it, substitute the 12 into the equation.

(12-5)*4+7=35

(7)*4+7=35

28+7=35

35=35.

Thus, your answer is , the number is 12.
iren [92.7K]3 years ago
3 0
11 is the number because I subtracted 7 and 35 it was 28 then divided 28 and 4 which is 6 then added 6 and 5
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Answer:

Mean = -1,115,000 per year.

Step-by-step explanation:

Mean = (Σx)/N

The mean is the sum of variables divided by the number of variables

Σx = sum of variable = change in number of visitors over a 10 year period = -11150000

N = number of variables = 10

Mean = (-11150000)/10

Mean = -1,115,000 per year.

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Surface area of 9cm, 10cm, and 15cm
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What number is equivalent to 3/4 b-2/3 b =-9
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r3t40
5 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

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3 years ago
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