Since Anna is either grouping them as single rock or as group of 10, we need to find the maximum number of groups of 10 as follows: 38/10 = 3.8
This means that Anna can make maximum 3 groups of 10 rocks.
Based on this, the different ways to group the rocks are as follows:
- 3 groups of 10 and 8 (which are calculated as: 38-30) single rocks
- 2 groups of 10 and 18 (which are calculated as: 38-20) single rocks
- 1 group of 10 and 28 (which are calculated as: 38-10) single rocks
- 0 group of 10 and 38 (which are calculated as: 38-0) single rocks
Answer:
P=40
a + b + x = P
a = 3x
b = x + 5
substitute for b & y
3x + (x+5) + x = 40
Step-by-step explanation:
longest section 1 = a
mid length section 2 = b
shortest section 3 = x
P=40
a + b + x = P
a = 3x
b = x + 5
substitute for b & y
3x + (x+5) + x = 40
5x + 5 = 40
5x = 35
x = 7
b = 12
a = 21
Given equation is
The given equation is in the form of
a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
<span>f(x) = 5x+1
f(-4) = 5(-4) + 1 = -20 + 1 = -19
hope that helps
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