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Shkiper50 [21]
3 years ago
7

PLEASE HELP ME!!!!!!! :(

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0
The answer should be C
Because you take the number of young people who work outdoors, which is 242 and divide it by the total, which appeared to be 1028.
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Find the circumference and area of a circle that has a radius of x+1
lbvjy [14]
Circumference: 2πr
Circumference: 2(3.14)(x + 1)
Circumference: 6.28(x + 1)
Circumference: 6.28(x) + 6.28(1)
Circumference: 6.28x + 6.28

Area: πr²
Area: 3.14(x + 1)²
Area: 3.14(x  +1)(x + 1)
Area: 3.14(x(x + 1) + 1(x + 1))
Area: 3.14(x(x) + x(1) + 1(x)  1(1))
Area: 3.14(x² + x + x + 1)
Area: 3.14(x² + 2x + 1)
Area: 3.14(x²) + 3.14(2x) + 3.14(1)
Area: 3.14x² + 6.28x + 3.14
6 0
3 years ago
Complete parallel side 2
Gnoma [55]

Step-by-step explanation:

Assume length of side 2 = L

Area of parallelogram is Height x L

So, 72 = 8 x L

L = 9

8 0
2 years ago
Can y’all help me with 17 and 18
lord [1]

Answer:

17 is 35 degrees and 18 is 43 degrees

7 0
2 years ago
Read 2 more answers
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
Using desmos
VMariaS [17]

The attached graph represents the location of the pH values 0 and 1

<h3>How to plot the points?</h3>

The given parameters are:

pH value 0 = (1, 0)

pH value 1 = (0.1, 1)

This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).

See attachment for the graph

Read more about graphs at:

brainly.com/question/4025726

#SPJ1

<u>Complete question</u>

The pH value is 0 at (1, 0) and 1 at (0.1, 1).

Using desmos

A. Locate, plot, and label on your graph where the pH value is 0.1

B. Locate, plot, and label on your graph where the pH value is 1.

8 0
2 years ago
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