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3 years ago

10

subtracting 1 to the product of 5 and x gives the same value as adding 10 to the product of 3 and x. what value of x makes the s

tatement true ?

1 answer:

Vilka [71]3 years ago

7 0

Answer:17

Step-by-step explanation: You just follow the steps.

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PLEASE HELP WILL GIVE BRAINLIEST<br><br> 15-10 dividid by 5 times 2^2 in the correct order

Sati [7]

Answer:

12 1/2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What do you know about the slopes of lines that are parallel? Explain

Rudiy27

Parallel lines have to have the same slope. The must stay the same distance apart at all times to be parallel and the only way to do that is to change in exactly the same manner as they move so slope is the change in x over the change in y. it must be the same

7 0

3 years ago

Which shows the proper use of the distributive property

Karo-lina-s [1.5K]

Answer:

-2 (6x - y) = -12x + 2y

Step-by-step explanation:

By using the distributive property, you start by multiplying -2 and 6x which gets you -12x. You then multiply -2 and -y (in other words -y = -1y) so, -2* -y would get you 2 as a negative multiplied by a negative is a positive. So, adding them together would get your final answer: -2 (6x - y) = -12x + 2y

5 0

3 years ago

How do i find the slope

Elodia [21]

Hi, I'm happy to help!

To find the slope, you need to use the slope formula, where m is the slope:

<u>m=</u> $\frac{y_{2}-y_{1 } }{x_{2} -x_{1} }$ <u></u>

Slope means rise over run, or how much the line rises per the amount the line moves forward. This equation shows the movement from the y points to show <u>rise</u>, over the difference in the x points to show <u>run</u>.

Now, to find the slope we insert our values, starting with our second y point:

<u>m=</u> $\frac{2-y_{1 } }{x_{2} -x_{1} }$ <u></u>

Now insert our first y point:

<u>m=</u> $\frac{2-4 }{x_{2} -x_{1} }$ <u></u>

Now we insert our second x point:

<u>m=</u> $\frac{2-4 }{-3 -x_{1} }$ <u></u>

And finally our first x point:

<u>m=</u> $\frac{2-4 }{-3 -3 }$

Now, we solve:

<u>m=</u> $\frac{-2 }{-6}$

So, our slope is -2/-6, to simplify it, we remove both negatives because they cancel each other out.

<u>m=</u> $\frac{2 }{6}$

Now, we simplify our fraction by dividing the top and bottom by 2:

<u>m=</u> $\frac{1}{3}$ <u></u>

So, our slope is 1/3. This means that for every 1 unit the line rises, it goes to the right 3 units. The y-intercept is where the line hits the y axis.

If the question is asking for slope intercept form for the equation, you use y=mx+b

y represents any y coordinate on your line, m represents your slope (1/3), x represents any x coordinate on your line, and b represents your y-intercept (3).

If you were to insert these values, you would get:

y= $\frac{1}{3}$ x+3

You use this to find what a y coordinate would be so you can draw your line.

For the next equation we do the same thing:

<u>m=</u> $\frac{y_{2}-y_{1 } }{x_{2} -x_{1} }$ <u></u>

Insert our values:

<u>m=</u> $\frac{4-1}{2-(-4)}$ <u></u>

Get rid of the double negative:

<u>m=</u> $\frac{4-1}{2+4}$ <u></u>

Solve:

<u>m=</u> $\frac{3}{6}$ <u></u>

Simplify:

<u>m=</u> $\frac{1}{2}$

Now that we know our slope, let's plug it in to our slope intercept form equation.

y= $\frac{1}{2}$ x+3

I hope this was helpful! Keep learning! :D

5 0

3 years ago

A parabola has a vertex at (4, 0) and passes through the point (6, 1). Which of the following is the equation of this parabola i

Doss [256]

Easy

y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a

thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4

7 0

3 years ago