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Wewaii [24]
3 years ago
12

Which measure can be used to measure the variation of this data? Find this measure.

Mathematics
1 answer:
andriy [413]3 years ago
5 0
What is the measure?
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Yesterday liam used 20 stripped marbles to fill bags. how many non-stopped marbles did he used to fill up the bags?
777dan777 [17]
The answer is 30 because i had this on a test
5 0
3 years ago
If x=12 in, y=16, and z=20 in, what is the surface area of the geometric shape formed by this net?
maria [59]

Given:

x = 12 in, y = 16 in and z = 20 in

To find:

The surface area of the geometric shape.

Solution:

Area of top rectangle = z × z

                                    = 20 × 20

Area of top rectangle = 400 in²

Area of middle rectangle = z × y

                                          = 20 × 16

Area of middle rectangle = 320 in²

Area of bottom rectangle = z × x

                                          = 20 × 12

Area of bottom rectangle = 240 in²

Area of left triangle = \frac{1}{2}yx

                                $=\frac{1}{2}\times16\times12

Area of left triangle = 96 in²

Area of right triangle = \frac{1}{2}yx

                                $=\frac{1}{2}\times16\times12

Area of right triangle = 96 in²

Surface area = 400 + 320 + 240 + 96 + 96

                     = 1152

The surface area of the geometric shape is 1152 in².

3 0
3 years ago
PLEASE HELP ME!!!
Taya2010 [7]
A: (450>/10)+5
B: 44 Students
6 0
3 years ago
Read 2 more answers
Dominic invested $520 in an account in the year 1995, and the value has been growing exponentially at a constant rate. The value
Tom [10]

Answer:

I believe the answer is $936.64

Step-by-step explanation:

I hope this helps!

6 0
3 years ago
|2s|+19=13<br> Help me please
Mnenie [13.5K]

 \textsf{Hey there!}

\mathsf{|2s| + 19= 13}\\\textsf{Solve both sides by -19}\\\mathsf{|2s|+19+ (-19)=13+(-19)}\\\mathsf{Cancel\ out:\ 19 + (-19) \  because\ that\ gives\ you\ 0}\\\mathsf{Keep: 13 + (-19)\ because\ that\  helps\ us\ solve\ for\ our\ answer}\\\mathsf{13 + (-19) = -6}\\\mathsf{Solve\ for\ absolute\ value: |2s| = -6}\\\mathsf{Any\ absolute\ values\ CANNOT\ be\ less\ than\ 0}\\\mathsf{\boxed{\boxed{\mathsf{Thus, \ this\ make\ your\ answer\ is: \boxed{\boxed{\bf{No\ solution}}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

4 0
3 years ago
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