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Kay [80]
3 years ago
11

Please help. BRAINLIEST TO BEST ANSWER

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
6 0

Answer:

b

Step-by-step explanation:

we have the point

(2,-4)

so when

x=2

y=4

so we can try on all equations

y_1=2|x-2|-4\\\\y_1=2|2-2|-4\\\\y_1=2|0|-4\\\\y_1=0-4\\\\y_1=-4

so equation 1 could be

y_2=\frac{1}{2} |x-2|-4\\\\y_2=\frac{1}{2}|2-2|-4\\\\y_2=\frac{1}{2}|0|-4\\\\y_2=0-4\\\\y_2=-4

so equation 2 could be

y_3=2|x+2|-4\\\\y_3=2|2+2|-4\\\\y_3=2|4|-4\\\\y_3=8-4\\\\y_3=4

so equation 3 is not

y_4=\frac{1}{2}|x+2|-4\\\\y_4=\frac{1}{2}|2+2|-4\\\\y_4=\frac{1}{2}|4|-4\\\\y_4=\frac{1}{2}(4)-4\\\\y_4=2-4\\\\y_4=-2

so equation 4 is not

So another point that we have is

(0,-3)

so we plug in

y_1=2|x-2|-4\\\\y_1=2|0-2|-4\\\\y_1=2|-2|-4\\\\y_1=4-4\\\\y_1=0

so this isn't

y_2=\frac{1}{2}|x-2|-4\\\\y_2=\frac{1}{2}|0-2|-4\\\\y_2=\frac{1}{2}|-2|-4\\\\y_2=\frac{1}{2}(2)-4\\\\y_2=1-4\\\\y_2=-3

so the answer is b

shepuryov [24]3 years ago
3 0
It’s B
I’m sure of it
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<h3>What are linear equations?</h3>

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