A compound is found to contain 9.227 % boron and 90.77 % chlorine by mass. What is the empirical formula for this compound?
1 answer:
Find the moles of Boron and of Chlorine:
Assume there are 100 g of the compound in all
Boron: 9.224% --> .09224 (convert percent to decimals)
.09224*100g = 9.224g Boron (theoretical amt)
9.224g* 1mol/10.81g (molar mass Boron) = .8533 moles Boron
You might be interested in
Answer:
If you feel something in relation to how someone else feels, that's called sympathy.
Answer:instruction manuals
Explanation:
Bcz we does not use this as a product
Answer:
They have pledged to save the environment
Explanation:
"Have pledged" is the simple past of "pledge"
It looks like that is already rounded, as there is no solid numbers beside the 2 after the decimal.
If this is wrong, tell me.
Answer:second one I think
Explanation:
I think