3 years ago

A compound is found to contain 9.227 % boron and 90.77 % chlorine by mass. What is the empirical formula for this compound?

English

1 answer:

kramer3 years ago

4 0

Find the moles of Boron and of Chlorine:

Assume there are 100 g of the compound in all

Boron: 9.224% --> .09224 (convert percent to decimals)

.09224*100g = 9.224g Boron (theoretical amt)

9.224g* 1mol/10.81g (molar mass Boron) = .8533 moles Boron

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