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IgorLugansk [536]
3 years ago
7

What are the domain, range, and asymptote of h(x) = 6x – 4?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0
<span>h(x)=<span>6<span>x−4</span></span></span>  or  <span>h(x)=6x−4</span> 
<span>If the former, the domain is all real numbers, often denoted by the symbol </span>R<span>. </span>
<span>the range is </span><span>(0,∞)</span> 
<span>asymptote is y = 0</span>
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Eva8 [605]

Answer:

x=3

Step-by-step explanation:

5 0
2 years ago
Evaluate the function f(x) =-x/2 -7x -2 find f(-9)
NeX [460]

Answer:

f(-9)=\frac{131}{2}

Step-by-step explanation:

In order to evaluate a function at a given x-value, plug in that value into the actual function

f(x)=-\frac{x}{2} -7x-2\\\\f(-9)=-\frac{9}{2} -7(-9)-2\\\\f(-9) = \frac{131}{2}

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2 years ago
On a coordinate plane, a circle has a center at (0, 0). Point (3, 0) lies on the circle.
9966 [12]

Answer:

The correct option is;

No, the distance from (0, 0) to (2, √6) is not 3 units

Step-by-step explanation:

The given parameters of the question are as follows;

Circle center (h, k) = (0, 0)

Point on the circle (x, y) = (3, 0)

We are required to verify whether point (2, √6) lie on the circle

We note that the radius of the circle is given by the equation of the circle as follows;

Distance \, formula = \sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}}

Distance² = (x - h)² + (y - k)² = r² which gives;

(3 - 0)² + (0 - 0)² = 3²

Hence r² = 3² and r = 3 units

We check the distance of the point (2, √6) from the center of the circle (0, 0) as follows;

\sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}} = Distance

Therefore;

(2 - 0)² + (√6 - 0)² = 2² + √6² = 4 + 6 = 10 = √10²

\sqrt{\left (2-0 \right )^{2} + \left (\sqrt{6} -0 \right )^{2}} = 10

Which gives the distance of the point (2, √6) from the center of the circle (0, 0) = √10

Hence the distance from the circle center (0, 0) to (2, √6) is not √10 which s more than 3 units hence the point  (2, √6), does not lie on the circle.

4 0
2 years ago
Read 2 more answers
If = 80°, and m∠BED = 25°, what is ?<br><br> 55°<br> 30°<br> 65°<br> 20°
Tomtit [17]
The complete question in the attached figure

we know that
<span>The measure of the external angle is the semidifference of the arcs that it covers.
so
</span><span>m∠BED =(1/2)*[mAC-mBD]-------> solve for mBD
mBD=mAC-2</span>m∠BED
mBD=80-2*25--------> mBD=30°

the answer is
mBD=30°

5 0
3 years ago
Find the slope of the line that passes through Point A (7, 4) and Point B (3, 2), using the formula m=y2-y1/x2-x1
Furkat [3]

Answer:

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m = y2 - y1/x2 - x1

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m = -2/-4

m = 1/2

8 0
2 years ago
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