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IgorLugansk [536]
3 years ago
7

What are the domain, range, and asymptote of h(x) = 6x – 4?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0
<span>h(x)=<span>6<span>x−4</span></span></span>  or  <span>h(x)=6x−4</span> 
<span>If the former, the domain is all real numbers, often denoted by the symbol </span>R<span>. </span>
<span>the range is </span><span>(0,∞)</span> 
<span>asymptote is y = 0</span>
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Choose the correct option.Immersive Reader (1 Point) (A) z-5=2 is an equation and z=5 is the solution of this equation (B) t+2&g
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Answer:

<h3>Find the explanation below</h3>

Step-by-step explanation:

A) Given the equation z - 5 = 2

To get the solution, we will add 5 to both sides and find z as shown;

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z - 5 + 5 = 2 + 5

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C) Given the expression  x-2=2, to get the solution to the expression, you will add 2 to both sides of the equation;

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Read 2 more answers
A quadratic function has x-intercepts 2 and 6 and its vertex is (4, 8). What is the corresponding quadratic expression? A. 2x2 −
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Given:

A quadratic function has x-intercepts 2 and 6 and its vertex is (4, 8).

To find:

The corresponding quadratic expression.

Solution:

If graph of a function intersect the x-axis at c, then (x-c) is a factor of the function.

A quadratic function has x-intercepts 2 and 6. It means (x-2) and (x-6) are two factors of the required quadratic function.

The function is defined as:

P(x)=a(x-2)(x-6)                    ...(i)

Where, a is a constant.

The vertex of the quadratic function is (4,8). It means the point (4,8) will satisfy the function.

Substituting x=4 and P(x)=8 in (i).

8=a(4-2)(4-6)

8=a(2)(-2)

8=-4a

Divide both sides by -4.

\dfrac{8}{-4}=a

-2=a

Putting a=-2 in (i), we get

P(x)=-2(x-2)(x-6)

P(x)=-2(x^2-6x-2x+12)

P(x)=-2(x^2-8x+12)

P(x)=-2x^2+16x-24

Therefore, the correct option is B.

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