When 5x^2 + 2= 4x is written in standard form, what are the values of a, b, and c

Mathematics

1 answer:

goblinko [34]3 years ago

7 0

The standard form of a quadratic equation is

$ax^{2}+bx+c=0$ ,

where $a$ , $b$ , and $c$ are coefficients. You want to get the given equation into this form. You can accomplish this by putting all the non-zero values on the left side on the equation.

In this case, the given equation is

$5x^{2}+2=4x$

Since $4x$ is on the right side of the equation, we subtract that from both sides. The resulting equation is

$5x^{2}-4x+2=0$

Looking at the standard form equation $ax^{2}+bx+c=0$ , we can see that

$a=5, b=-4, c=0$

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0.1694 = 16.94% probability of a positive result for three samples combined into one mixture.

Step-by-step explanation:

For each test, there are only two possible outcomes. Either it is positive, or it is negative. The probability of a test being positive or negative is independent of any other test, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability of an individual blood sample testing positive for the virus is 0.06.

This means that $p = 0.06$

If samples from three people are combined and the mixture tests negative, we know that all three individual samples are negative. Find the probability of a positive result for three samples combined into one mixture.

It will be positive if at least one of the tests is positive, that is:

$P(X \geq 1) = 1 - P(X = 0)$