Question

When 5x^2 + 2= 4x is written in standard form, what are the values of a, b, and c

Answer 1

The standard form of a quadratic equation is

$ax^{2}+bx+c=0$,

where $a$, $b$, and $c$ are coefficients. You want to get the given equation into this form. You can accomplish this by putting all the non-zero values on the left side on the equation.

In this case, the given equation is

$5x^{2}+2=4x$

Since $4x$ is on the right side of the equation, we subtract that from both sides. The resulting equation is

$5x^{2}-4x+2=0$

Looking at the standard form equation $ax^{2}+bx+c=0$, we can see that

$a=5, b=-4, c=0$