Answer:
(1/2) qt/(3/4) hr = (1/2)*(4/3) qt/hr = (2/3) qt/hr
The rule for division of fractions is: invert the denominator and multiply.
When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
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1303/12.8 is the answer for that one which it should land in the middle of the line!
Let's assume that the faster car has a 2 mile "head start".
The faster car is 1.2 times faster (48/40) than the slower car.
It will take five 2 mile trips to "catch" the other car.
Five 2 mile trips will take 5 * 40 seconds = 200 seconds.
2 bc you can’t write it as a fraction
