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3 years ago

35 Tashaonda buys a case of oranges for $18.50 and a case of apples for $12.00.

Mathematics

1 answer:

saw5 [17]3 years ago

4 0

Answer:

$12.95 is the final cost for the oranges

$12 is the cost for apple

Step-by-step explanation:

The final cost for the orange is

30/100 x 18.50

=5.55

18.50-5.55

=$12.95

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The smaller triangle is a dilation of the larger triangle with a center of dilation at (2,−1) .

andrew-mc [135]

Answer:

Option B. 1/2

Step-by-step explanation:

The smaller triangle is a dilation of the larger triangle with the center of dilation at (2, -1).

we have to calculate the scale factor of the dilation.

One point of the large triangle is (-4, -1). After dilation it has become (-1, -1) of the smaller one.

If we consider the x coordinates of the point x = -4 has reduced down to -1 therefore scale factor = side of small triangle/side of the large triangle = (2 + 1)/(2 + 4) = 3/6 = 1/2

Therefore Option B. 1/2 is the answer.

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

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2 years ago

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yanalaym [24]

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