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statuscvo [17]
1 year ago
10

One number i ix le than a econd number. Four time the firt i 2 more than 6 time the econd. Find the number

Mathematics
1 answer:
Kruka [31]1 year ago
8 0

When the difference between one and two numbers is two, the two numbers are -10 and -12.

Given that,

The difference between one and two numbers is two. Twelve more than six times the second is four times the first.

We have to find the number.

We know that,

The system of equation we get

x=y-2 ----->equation(1)

4x=12+6y ----->equation(2)

Substitute for x in the equation(2)

4(y-2)=12+6y

4y-8=12+6y

4y-6y=12+8

-2y=20

y=-10

Substitute y=-10 in equation(1)

x=-10-2

x=-12

Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.

To learn more about number visit: brainly.com/question/17429689

#SPJ4

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The product of a number and twice that number is 180000, write the multiplication problem
ElenaW [278]
Six hundred times 300 equals 180,000
3 0
3 years ago
Read 2 more answers
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
Please I really need help with these
MrRissso [65]

Answer:

Idk lol

Step-by-step explanation:

8 0
3 years ago
How can you tell that −10 and −20 are solutions to this inequality, but 10 is not? 3n − 40 < −5n + 8
pochemuha

Step-by-step explanation:

-10 or -20 satisfies the equation.

But when you substitute 10 in:

30-40<-50+8

-10<-42(wrong)

it's wrong

6 0
3 years ago
HELP PLEASE ILL GIVE YOU BRAINLIST !! I DONT UNDERSTAND IT .
inn [45]

Step-by-step explanation:

35 + 35 = 70

180 - 70 = 110

180 - 110 = 70

70  + 70 = 140

180 - 140 = 40

so the answer is 40

7 0
3 years ago
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