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laila [671]
3 years ago
9

The square of a number exceeds that number by 12. What are the two possible solutions?

Mathematics
2 answers:
Serjik [45]3 years ago
5 0
X - the number

x^2=x+12 \\
x^2-x-12=0 \\
x^2+3x-4x-12=0 \\
x(x+3)-4(x+3)=0 \\
(x-4)(x+3)=0 \\
x-4=0 \ \lor \ x+3=0 \\
x=4 \ \lor \ x=-3

The two possible solutions are -3 or 4.
kherson [118]3 years ago
5 0

-3 or 4 hope this helps

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