The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible val
ue for the width?
A) 2w+2 x (5w) <_ 96
B) 2w+2 x (5w) >_96
C) 2w+2 x (5w) < 96
D) 2w+2 x (5w) > 96
WILL GIVE BRAINLIEST!!!
1 answer:
Let width be W
Then length = 5W
P=2L+2W
P< 96cm
Then the Perimeter of the rectangle is equal to
(2L+2W)< 96
2*(5W)+2W)≤96
Therefore, 2w+2⋅(5w)≤96
should be your answer
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