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Sonja [21]
3 years ago
9

Diane deposits $7000 into an account that pays simple interest at a rate of 6% per year. How much interest will she be paid in t

he first 3 years?​
Mathematics
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

1,260

Step-by-step explanation:

6x3=18 7000÷18=1,260

IRINA_888 [86]3 years ago
3 0

Answer:

18% or 1260$

Step-by-step explanation:

first u find 6% of 7000 then you multiply it by 3 for those three years .

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2 ways to decompose the number 749
kolezko [41]
Okay. You can decompose 749 with these ways:
700 + 40 + 9
or
500 + 200 + 40 + 9
6 0
3 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
What is the answer to y=-2/3+b
Mashcka [7]

Answer:

it is B

Step-by-step explanation:

8 0
2 years ago
What happens when the ordered pair (x,y) moves to the right?
UNO [17]
Question is unclear
4 0
3 years ago
Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.
Romashka [77]

Answer:

<u>(3,7)</u> (7,3) (−1,14) <u>(0,1)</u> <u>(12,25)</u>

<u>(5,11)</u> (0,12) (1,8) (12,0) <u>(−1,−1)</u>

Step-by-step explanation:

We have the following function:

y = 2x+1.

We are going to check if each ordered pair is a solution.

(3,7)

If when x = 3, y = 7, it is a solution.

y = 2x + 1 = 2(3) + 1 = 7

This ordered pair is a solution.

(7,3)

If when x = 7, y = 3, it is a solution.

y = 2x + 1 = 2(7) + 1 = 15

This ordered pair is not a solution.

(-1,14)

If when x = -1, y = 14, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is not a solution.

(0,1)

If when x = 0, y = 1, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is a solution.

(12,25)

If when x = 12, y = 25, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is a solution.

(5,11)

If when x = 5, y = 11, it is a solution.

y = 2x + 1 = 2(5) + 1 = 11

This ordered pair is a solution.

(0,12)

If when x = 0, y = 12, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is not a solution.

(1,8)

If when x = 1, y = 8, it is a solution.

y = 2x + 1 = 2(1) + 1 = 3

This ordered pair is not a solution.

(12,0)

If when x = 12, y = 0, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is not a solution.

(-1,-1)

If when x = -1, y = -1, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is a solution.

3 0
2 years ago
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