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leonid [27]
3 years ago
10

What's the area of "CDEF"

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0
My quest is somewhere between 30 or 50
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9+19 - 12 + 12 + 12323 - 39
Alexxandr [17]

Answer : 12312

Step-by-step explanation : According to BODMAS, Addition (+) comes first

Hence --  9 + 19 + 12 + 12323 = 12363

               12363 - 12 - 39  = 12363 - 51

                                          = 12312

       

5 0
3 years ago
When a sunfloweris 2 weeks old it is 38 centimeters tall when it is 6 weeks old it is 114 cm tall how tall is it when it is 3 ½
Anna11 [10]
2 wk --- 38 cm
3.5 wk --- x cm
x =  3.5 wk x 38 cm
       ---------------------
       2 wk
x= 66.5 cm
5 0
3 years ago
Please help me with this one<br> 10x+5y=72<br> 15x+4y=80
Andre45 [30]
I hope this helps you

7 0
3 years ago
Read 2 more answers
Three-fourths of the tickets had been sold, and there were 420 tickets left. How many tickets were printed?
Reil [10]

Answer:

Step-by-step explanation:

420 = 1/4 so 4/4 is 4 420s

420 x 4 = 1680

8 0
3 years ago
Read 2 more answers
Find dy/dx if f(x) = (x + 8)^3x.
vlabodo [156]
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...

Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.

Let y = (x+8)^(3x)

Take the natural log of both sides:

ln(y) = ln((x+8)^(3x))

By laws of logarithms, this can be rearranged:

ln(y) = 3xln(x+8)

Next, differentiate both sides. By implicit differentiation:

d/dx(ln(y)) = 1/y dy/dx

The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):

d/dx(3xln(x+8)) = d/dx(uv)

du/dx = 3

Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:

v = ln(a)
da/dx = 1
dv/da = 1/a

By chain rule:

dv/dx = dv/da * da/dx = 1/a = 1/(x+8)

Finally, use the product rule:

d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)

This overall produces the equation:

1/y * dy/dx = 3x/(x+8) + 3ln(x+8)

We want to solve for dy/dx, achievable by multiplying both sides by y:

dy/dx = y(3x/(x+8) + 3ln(x+8))

Since we know y = (x+8)^(3x):

dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))

Neatening this up a bit, we factorise out 3/(x+8):

dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))

Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.

I hope this helped you :)
8 0
3 years ago
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