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VikaD [51]
3 years ago
11

5/6 N=10 solve this problem. I could not put the six under the five where it belongs. please show the work

Mathematics
1 answer:
Andreyy893 years ago
3 0

5/6N = 10

Mutiply by 6/5

So N=12

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6 0
3 years ago
Jillian is selling boxes of cookies to raise money for her basketball team. The 10 oz. box costs $3.50, while the 16 oz. box cos
RideAnS [48]

Answer:

Jillian sold 15 ten-oz bags and 9 sixteen-oz bags.

Step-by-step explanation:

Let x represent number of 10-oz bags and y represent number of 16-oz bags.

We have been given that Jillian sold 24 boxes of cookies in total. We can represent this information in an equation as:

x+y=24...(1)

We are also told that 10 oz. box costs $3.50, while the 16 oz. box costs $5.00, so the cost of x 10-oz bags would be 3.50x and cost of y 16-oz bags would be 5y.

At the end of one week, she collected $97.50. We can represent this information in an equation as:

3.5x+5y=97.50...(2)

Now, we will use substitution method to solve our system of equations. From equation (1), we will get:

y=24-x

Substitute this value in equation (2):

3.5x+5(24-x)=97.50

3.5x+120-5x=97.50

-1.5x+120=97.50

-1.5x+120-120=97.50-120

-1.5x=-22.5

\frac{-1.5x}{-1.5}=\frac{-22.5}{-1.5}

x=15

Therefore, the number of 10-oz boxes sold be Jillian is 15.

Now, we will substitute x=15 in equation (1) to solve for y.

15+y=24

15-15+y=24-15

y=9

Therefore, the number of 16-oz boxes sold be Jillian is 9.

8 0
3 years ago
Identify the property demonstrated. (7x3)^4 = 7^4 x 3^4
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( 7 x 4 ) ^4 = 7^4  x  3^4
The rule is:
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Answer:
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Daniel [21]

Answer:

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Step-by-step explanation:

\bf \cfrac{AB}{DE}  =  \cfrac{BC}{EF}

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  • \bf  \cfrac{3}{2}  =  \cfrac{BC}{12}
  • \bf BC =  \cfrac{3}{2}  \times 12
  • \bf 3 \times 6
  • \bf BC = 18
  • \bf \angle B = \angle \: E

So, ∆ABC ~ ∆DEF by SAS.

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2 years ago
Need help help for 30 points
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