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4 years ago

7

Choose all the statements that correctly explain why this shape is an obtuse isosceles triangle.it has 3 sides that are all equa

l.1 of the angles is equal to 90°.1 angle is greater than 90°.2 sides are equal in length.

1 answer:

NemiM [27]4 years ago

8 0

An Isosceles triangle has two congruent sides and angles so, therefore, the last two statements should be correct.

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A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

3 years ago

5/12+8/12 I need help

Ronch [10]

$\frac{13}{12}$ is the answer

Hope this helps

6 0

3 years ago

Read 2 more answers

Natalie visits a grocery store to buy tomatoes.The cost of tomatoes is $26.She remitted the bill and received $4 in change from

yKpoI14uk [10]

$30
You need to add $4 to $26 since the tomatoes were 26 dollars and she received 4 back

5 0

3 years ago

The value of the definite integral / 212x – sin(x) dx / 122x-sin(x) is

blondinia [14]

Hi there!

$\boxed{= 70 + cos(12) - cos(2) \approx 71.26}$

$\int\limits^{12}_{2} {x-sin(x)} \, dx$

We can evaluate using the power rule and trig rules:

$\int x^n = \frac{x^{n+1}}{n+1}$

$\int x = \frac{1}{2}x^{2}$

$\int -sin(x) = cos(x)$

Therefore:

$\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}$

Evaluate:

$(\frac{1}{2}(12^{2})+cos(12)) - (\frac{1}{2}(2^2)+cos(2))\\= (72 + cos(12)) - (2 + cos(2))\\\\= 70 + cos(12) - cos(2) \approx 71.26$

3 0

3 years ago

Which of the following is NOT a factor of b3 +6b²?<br> 63<br> 062<br> Ob<br> (b + 6)

Gnesinka [82]

Answer:

b³

Step-by-step explanation:

The lowest common multiple of the expression is b². This because, taking out a factor of b, b ( b² + 6b ), taking out a factor of b², b² ( b + 6 ),

taking out a factor of ( b + 6 ), ( b + 6 ) b². As a result b² is only the option which is not a factor.

7 0

2 years ago