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natka813 [3]
3 years ago
8

294 blue balls, 252 pink balls and 210 yellow balls are distributed equally among some students with none left over. What is the

biggest possible number of students?
Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0
You have to find the greatest number that divide 294, 252 and 210, i.e., the greatest common factor.

Then, you need to factor each number and calculate the product of the common factors raised to the lowest exponent.

294 = 2*3*7^2
252 = 2^2 * 3^2 * 7
210 = 2*3*5*7

Greatest common factor = 2*3*7 = 42

The biggest possible number of students to distribuute the balls equally is 42

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When Ryan counted some dimes and quarters he had 196 coins and a total of $39.40. How many coins of each kind does Ryan have?
Nonamiya [84]
Quarters = x
dimes = 196 - x

10(196 - x) + 25x = 3940
1960 - 10x +25x = 3940
1960 + 15x = 3940
15x = 1980
x = 132

169 - 132 = 64

Therefor there are 132 quarters and 64 dimes
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