The answer is 1050 minutes
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
X=80, y=140,z=20
I hope it helps
Answer:
(-4,2)
Step-by-step explanation:
First we have to find a common multiple to use to add and find the system of equations. We need to eliminate one of the variables in order to solve.
Since 5 * 3 = 15, and 3 * -5 = 15, -15x and 15x will cancel each other out. Therefore x will be eliminated.
Before:
5x + 2y = -16
3x + 7y = 2
After:
15x + 6y = -48 <----------Now we solve for y
-15x + -35y = -10
+----------------------
-29y = -58
-29 -29
y = 2
Now what we do is we choose and equation and solve for x, since it is still unknown. Any equation is fine but I will choose the second one since it has easy numbers.
3x + 7y = 2
3x + 7(2) = 2
3x + 14 = 2
-14 -14
----------------------
3x = -12
3 3
x = -4
Therefore our final answer is (-4,2)
Answer:
25 mpg
Step-by-step explanation:
We have a set of values 19, 21, 22, 28 and 18
The average (which is the mean of the set of values ) is :
19 + 21 + 22 + 28 + 18 = 21.6 mpg out of the government requirement
So we need a value such as the mean become at least 25 mpg
We have to solve the equation:
(19+21+22+28+ x)/ 5 = 25
(90 + x ) /5 = 25 ⇒ 90 + x = 125 ⇒ x = 35 mpg
If we get the mean of the set of values including 35 we have:
(19 +21+ 22+ 28 + 35 ) / 5 = 25 mpg government requirement
