If the two equations in parenthesizes were there own equations which ones would equal 1 and 6
(x-1) or x=1
(3x-1) or x=1/3
3(x-1) or 3x-3 or x=1
Do you understand?
Py +7 = 6y + qp
Solve the equation for y
To solve the equation for y we need to get y alone
Py +7 = 6y + qp
Subtract 6y from both sides
Py - 6y +7 = + qp
Subtract 7 from both sides
Py - 6y = + qp - 7
Now factor out y
(P - 6)y = qp - 7
Divide by P - 6 from both sides
Answer:
<u>I Believe your answer is B, put all the numbers in order then find the middle number</u>
Step-by-step explanation:
it may be thought of as the "middle" value of a data set. For example, in the data set {1, 3, 3, 6, 7, 8, 9}, the median is 6,
This is a little long, but it gets you there.
- ΔEBH ≅ ΔEBC . . . . HA theorem
- EH ≅ EC . . . . . . . . . CPCTC
- ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
- ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
- ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
- ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
- ΔDAC ≅ ΔDAG . . . HA theorem
- DC ≅ DG . . . . . . . . . CPCTC
- ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
- ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
- ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
- ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
- (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
- ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
- This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
For this question you should know:
1/2 = 5/10
and
4/5 = 8/10
so you can see 8/10 is greater than 5/10 so the answer is no
4/5 is greater than 1/2 :)))
i hope this is helpful
have a nice day
