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horrorfan [7]
3 years ago
12

Subtract. Express your answer in lowest terms.

Mathematics
2 answers:
Helen [10]3 years ago
5 0

Answer:

i believe the answer 19/3  

Step-by-step explanation:


mylen [45]3 years ago
5 0

8 1/2 = 17/2

2 1/6 = 13/6

17/2 - 13/6 = 19/3 OR 6 1/3


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Hai came someone help I too lazy to do it...
baherus [9]

Answer: 4 Cups

I think in order to solve this, you would need to add up the fractions that they used. So it would be,

\frac{1}{4}+\frac{1}{4}+\frac{3}{8}+\frac{3}{8}+\frac{5}{8}+\frac{5}{8}+\frac{5}{8}+\frac{7}{8}   Transform the Expressions

\frac{1+1}{4} +\frac{3+3+5+5+5+7}{8}    Calculate the sum

\frac{2}{4} +\frac{28}{8}    Reduce

\frac{1}{2}+\frac{7}{2}   Transform the Expression

\frac{1+7}{2}   Calculate

\frac{8}{2}  Reduce the Fraction

4

Please mark brainliest if this helped you :)

3 0
3 years ago
Explain why a positive times a negative is a negative number.
prohojiy [21]

Explanation:

This can be explained by thinking numbers on the number line as:

Lets take we have to multiply a positive number (say, 2) with a negative number say (-3)

<u>2×(-3)</u>

Suppose someone is standing at 0 on the number line and to go to cover -3 , the person moves 3 units in the left hand side. Since, we have to compute for 2×(-3), The person has to cover the same distance twice. At last, he will be standing at -6, which is a negative number.

A image is shown below to represent the same.

<u>Thus, a positive times a negative is a negative number.</u>

8 0
4 years ago
The floor of a room is being covered with tile. An area one half
tangare [24]

Answer:

Only the floor area \frac{3}{8} has been covered

Step-by-step explanation:

Assuming that the floor of the room is rectangular, then its area is equal to the product of its length times its width.

A = lw

Let's now call A 'the area that was covered with tiles.

We know that half the length was covered, then:

l' = \frac{1}{2}l

w' = \frac{3}{4}w

So:

A' = \frac{1}{2}l(\frac{3}{4}w)

A' = \frac{3}{8}lw

Finally:

A' = \frac{3}{8}A


4 0
3 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Mr. Charles bought dinner for his family.
ladessa [460]
He pays $53.99 hope that help you
6 0
3 years ago
Read 2 more answers
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