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3 years ago

What is the answer to 3/8 plus 5/12

Mathematics

2 answers:

devlian [24]3 years ago

7 0

The answer is A 19/24 because if you do 3/8 + 5/12 =9/24 + 10/24= 19/23

FinnZ [79.3K]3 years ago

6 0

19/24, because 3/8 equals 9/24 and 5/12 equals 10/24. 10 plus 9 equals 19.

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Gabe rounds 9.456 to the nearest hundredth. Then, he rounds the result to the nearest tenth. Last, he rounds that result to the

larisa86 [58]

Answer:

390

Step-by-step explanation:

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2 years ago

Given g(x) = x² - 6x - 16, which statement is true?

inn [45]

The correct choice of this question with the given polynomial is "The zeros are -2 and 8, because the factors of g are (x + 2) and (x - 8)". (Correct choice: H)

<h3>How to analyze a second orden polynomial with constant coefficients</h3>

In this case we have a second order polynomial of the form x² - (r₁ + r₂) · x + r₁ · r₂, whose solution is (x - r₁) · (x - r₂) and where r₁ and r₂ are the roots of the polynomial, which can be real or complex numbers but never both according the fundamental theorem of algebra.

If we know that g(x) = x² - 6 · x - 16, then the factored form of the expression is g(x) = (x - 8) · (x + 2). Hence, the correct choice of this question with the given polynomial is "The zeros are -2 and 8, because the factors of g are (x + 2) and (x - 8)". $\blacksquare$

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4 0

2 years ago

Can someone help me?

andreyandreev [35.5K]

I’m sorry I can’t see it well enough (my eyesight is bad)

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2 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago

I just need help with this problem

Oksanka [162]

+1/31 and -1/31
Hope this helps.

7 0

3 years ago