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Elena-2011 [213]
3 years ago
12

Which of the following is not an appropriate name for the line

Mathematics
1 answer:
charle [14.2K]3 years ago
3 0

Answer:

Step-by-step explanation:

What's the line look like?

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Fill in the blanks □+0=3/4.also mention the property used.
Dafna1 [17]

Answer:

3/4 + 0 = 3/4 Additive Neutral Property

Step-by-step explanation:

3 0
2 years ago
9•(-5)<br><br> A. -45<br> B. -95<br> C. 4<br> D. 45
alexgriva [62]

Answer:

A. -45

Step-by-step explanation:

multiplying a positive an a negative number gives out a negative result

so when we multiple 9 with -5 the result is -45

3 0
2 years ago
Read 2 more answers
Ill give brainilest, question is in the picture.
yuradex [85]

Step-by-step explanation:

1. true

2. false

3.true

4.false

5. ( may be false)

6 .(may be false)

3 0
2 years ago
The product of two given numbers is 126 both of them are divisible by 3 but neither of them is 3.The larger of the two numbers i
Mice21 [21]

I believe the answer is 21

21 × 6 = 126

and both numbers are divisible by 3

4 0
2 years ago
2. Maria is monitoring the temperature of
stiks02 [169]

Here, we are required to determine after how many minutes will the two substances be at the same temperature.

The equation of when the two substances will be at the same temperature and the solution are as follows;

(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).

(b) The solution is, x = 3.285minutes.

For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;

  • T(a) = 96.2 + 1.5(x)

For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;

  • T(b) = 98.5 + 0.8(x)

(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).

  • T(a) = T(b)

The equation is therefore;.

96.2 + 1.5(x) = 98.5 + 0.8(x)

(b) To determine the solution;

1.5x - 0.8x = 98.5 - 96.2

0.7x = 2.3

x = 2.3/0.7

x = 3.285minutes.

Read more:

brainly.com/question/20248109

5 0
1 year ago
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